How to calculate the directional derivatives of the function fie (x,y, z) = xy^2+yz^3 at points (1,-1,1) in the direction (3, 1,-1) - Quora
![1. u = √(sin^2x + sin^2y + sin^2z) then ∂u/∂z at (0,0, pi/4) = A 2. u = (x - y)(y - z)(z - x) then ux + uy + uz = 1. u = √(sin^2x + sin^2y + sin^2z) then ∂u/∂z at (0,0, pi/4) = A 2. u = (x - y)(y - z)(z - x) then ux + uy + uz =](https://dwes9vv9u0550.cloudfront.net/images/1842802/4a2c90af-35a4-4058-8514-da4d694de5cf.jpg)
1. u = √(sin^2x + sin^2y + sin^2z) then ∂u/∂z at (0,0, pi/4) = A 2. u = (x - y)(y - z)(z - x) then ux + uy + uz =
![Implicit Differentiation With Partial Derivatives Using The Implicit Function Theorem | Calculus 3 - YouTube Implicit Differentiation With Partial Derivatives Using The Implicit Function Theorem | Calculus 3 - YouTube](https://i.ytimg.com/vi/OBELQIPH5xY/maxresdefault.jpg)